a) translational equibrium? c, d, e right? but because force has to be balanced

Question

a) translational equibrium? c, d, e right? but because force has to be balanced out evenly,

but i dont get why e is translational eq ..? the point of A (i believe its axis) its not in the center.

b) rotational equilbrium ? a, e i know torque is has to be balance t=f*l right? which l=r*sin

from picture, part a seems have the equal distance also the force.. and part c looks balanced to but c was not the answer... im not sure why. also i still dont get why e is the answer in this case.

c) both? e.

d) neither ? b this part i dont get why is b. i know its not translational for sure.. but cant be rotational?

answer with your knowledge not copying from other places,, yahoo, other chegg answers, i've already check everthing but i';m still confused so i'm posting this

Explanation / Answer

Translation eqquilibrium is an equilibrium in which the centre of mass does not move or moves with constant velocity...that is there is no net force acting on the body....

so in the figure c,d,e are in translational equilibrium....

c -- both forces are equal and opposite

d--- sum of all the forces is zero vectorically.

e--- both forces are eual and opposite

Rotational equilibrium is an equilibrium in which the body does not rotate about its centre of mass or in other words there is net torque acting on the body...

so in the figure a and e are in rotational equilibrium.....

a----both forces are equal , equdistant from centre of mass and in same direction

e----- both forces pass through the centre of mass...so no perpendicular distance...hence no torque

as e is in both translational and rotational eqqulibrium ....it is in complete dynamic equilibrium

b is neither because there is a net force acting on the body....and as the centre of mass is not exactly at the centre....the forces are equal but not equidistant...so each force causes a torque of different value...hence net torque is not zero...hence it is in neither equilibria...

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