M, a solid cylinder (M=2.43 kg, R=0.117 m) pivots on a thin, fixed, frictionless
ID: 1311712 • Letter: M
Question
M, a solid cylinder (M=2.43 kg, R=0.117 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.730 kg mass, i.e., F = 7.161 N.
A) Calculate the angular acceleration of the cylinder. Because the bearing is thin, the moment of inertia of the bearing is essentially that of a solid cylinder
C)How far does m travel downward between 0.630 s and 0.830 s after the motion begins?
D)The cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.446 m in a time of 0.550 s. Find Icm of the new cylinder.
Explanation / Answer
A) a = g[1 - M/(M+2m)] = 3.6819 m/s
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