A crate of mass 45.0 kg is being transported on the flatbed of a pickup truck. T

Question

A crate of mass 45.0 kg is being transported on the flatbed of a pickup truck. The coefficient of static friction between the crate and the truck's flatbed is 0.270, and the coefficient of kinetic friction is 0.220.

The truck accelerates forward on level ground. What is the maximum acceleration the truck can have so that the crate does not slide relative to the truck's flatbed?

The truck barely exceeds this acceleration and then moves with constant acceleration, with the crate sliding along its bed. What is the acceleration of the crate relative to the ground?

Explanation / Answer

psuedo force on crate = ma

ma = frictional force

ma = 0.27*mg

a = 0.27g = 2.7 m/s2

now since crate is moving coefficient of friction = 0.22

net force= ma - 0.22mg

net acc = 2.7 - 0.22*10

= 0.5 m/s2

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