A car with a mass of 1050kg and a speed of v 1 = 18.0m/s approaches an intersect

Question

A car with a mass of 1050kg and a speed of v1 = 18.0m/s approaches an intersection, as shown in the figure(Figure 1) . A 1330kg minivan traveling atv2 is heading for the same intersection. The car and minivan collide and stick together. The direction of the wreckage after the collision is ? = 42.5? above the x axis.

Part A

Find the initial speed of the minivan, assuming external forces can be ignored.

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Part B

Find the final speed of the wreckage.

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Figure 1 of 1

A car with a mass of 1050kg and a speed of v1 = 18.0m/s approaches an intersection, as shown in the figure(Figure 1) . A 1330kg minivan traveling atv2 is heading for the same intersection. The car and minivan collide and stick together. The direction of the wreckage after the collision is ? = 42.5? above the x axis.

Part A

Find the initial speed of the minivan, assuming external forces can be ignored.

SubmitMy AnswersGive Up

Part B

Find the final speed of the wreckage.

SubmitMy AnswersGive Up

Provide FeedbackContinue

Figure 1 of 1

Explanation / Answer

Initial momentum in x - direction = m1v1

Final momentum in x - direction=(m1+m2)vfcosQ

nitial momentum in y - direction = m2v2

Final momentum in y - direction=(m1+m2)vfsinQ

From conservation of momentum,

In x-direction, m1v1=(m1+m2)vfcosQ -----------------------------(1)

In y-direction, m2v2=(m1+m2)vfsinQ ----------------------------(2)

Eqn (2) /(1),

v2/v1=tanQ

=>v2=18*tan42.5=16.5m/s

Now, from eqn (1),

m1v1=(m1+m2)vfcosQ

=>1050*18=(1050+1300)vfcos42.5

=>vf=1050*18/2350*cos42.5

   vf=10.9m/s

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