A 51-kg box is being pushed a distance of 7.3 m across the floor by a force P wi

Question

A 51-kg box is being pushed a distance of 7.3 m across the floor by a force P with arrow whose magnitude is 153 N. The force P with arrow is parallel to the displacement of the box. The coefficient of kinetic friction is 0.22. Determine the work done on the box by each of the four forces that act on the box. Be sure to include the proper plus or minus sign for the work done by each force. (The floor is level and horizontal. Forces that act on the box: pushing force P, frictional force f, normal force N, and weight mg.)

Wp =

Wf =

Wn =

Wmg =

Explanation / Answer

The work being done by gravity and normal force is zero because displacement is along the horizontal axis and those two forces run along the vertical axis.

I believe the frictional force is 122.5 because F = (coefficient of friction) mg = .22 (51)(9.8). Then we use w = Fs = -7.3 (109.956) = - 802.6788 J ..... This force is being applied in the opposite direction than the applied force.

And the applied force is: w = fs = (153) (7.3) = 1116.9 J

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