A tank is filled with water to a height H, 40 m. A hole is punched in one of the

Question

A tank is filled with water to a height H, 40 m. A hole is punched in one of the walls at a depth h, 8.00 m, below the water surface (see the figure). What is the distance x from the base of the tank to the point at which the resulting stream strikes the floor?

b. Could a hole be punched at another depth to produce a second stream that would have the same range? If so, at what depth?

c. At what depth should a hole be punched to make the emerging stream strike the ground at the maximum distance from the base of the tank?

Explanation / Answer

we know that the speed of ejection = sqrt(2gh) = v

now distace traveresed = v * sqrt(2(H-h)/g) = 2 sqrt(h(H-h))

a) h= 8 m => distance = 32 m

b) we have h(H-h) = 256 => sum prod. of roots = 256 = h1*h2 .. here h1 = 8 => h2 = 32 m

c) maximum occurs at h=H/2 => h = 20 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.