An arrow is shot at an angle of 45degrees above the horizontal. The arrow hits a

Question

An arrow is shot at an angle of 45degrees above the horizontal. The arrow hits a tree a horizontal distance D=220m away, at the same height above the ground as it was shot. Use g=9.8m/s2 for the magnitude of the acceleration due to gravity. Suppose someone drops an apple from a vertical distance of 6.0 meters, directly above the point where the arrow hits the tree. How long after the arrow was shot should the apple be dropped, in order for the arrow to pierce the apple as the arrow hits the tree? I keep on getting 5.83 sec. but my sig figs are incorrect somehow

Explanation / Answer

HERE THE TIME TAKEN BY THE ARROW TO REACH THE LEVEL IS TAKEN OUT USING EQUATION OF PROJECTILE. AND THEN SINCE FALLING OF APPLE IS FREE FALL, APPLY EQN OF MOTION TO GET TIME GOR APPLE TO TRAVEL 6MTRS. THIS TIME COMES OUT TO BE 1.1 SEC AND THE TIME OF PROJECTILE IS 6.7 SEC DIVIDING THEM IS THE ANSWER

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