The mass of copper atom is 2.51*10^-25 kg and the density of copper is 8920 kg/m
ID: 1316036 • Letter: T
Question
The mass of copper atom is 2.51*10^-25 kg and the density of copper is 8920 kg/m^3 A.) determine the number of atoms in 1 cm^3 of copper Cu-atom/cm^3 B.) visualize the one cubic centimeter as formed by stacking identical cubes , with one copper atom at the center of each . Determine the volume of each cube. Cm^3/Cu-atom C.) find the edge dimension of each cube, which represents as estimate for the spacing between atoms. The mass of copper atom is 2.51*10^-25 kg and the density of copper is 8920 kg/m^3 A.) determine the number of atoms in 1 cm^3 of copper Cu-atom/cm^3 B.) visualize the one cubic centimeter as formed by stacking identical cubes , with one copper atom at the center of each . Determine the volume of each cube. Cm^3/Cu-atom C.) find the edge dimension of each cube, which represents as estimate for the spacing between atoms. The mass of copper atom is 2.51*10^-25 kg and the density of copper is 8920 kg/m^3 A.) determine the number of atoms in 1 cm^3 of copper Cu-atom/cm^3 B.) visualize the one cubic centimeter as formed by stacking identical cubes , with one copper atom at the center of each . Determine the volume of each cube. Cm^3/Cu-atom C.) find the edge dimension of each cube, which represents as estimate for the spacing between atoms. A.) determine the number of atoms in 1 cm^3 of copper Cu-atom/cm^3 B.) visualize the one cubic centimeter as formed by stacking identical cubes , with one copper atom at the center of each . Determine the volume of each cube. Cm^3/Cu-atom C.) find the edge dimension of each cube, which represents as estimate for the spacing between atoms.Explanation / Answer
a) mass of 1 cm^3 of cupper = 8.92 * 10-3 kg (from density= mass/volume equation)
therefore number of atom = 8.92*10-3 / 2.51*10-25 = 3.554*1022
b) let's take number of small cube = N, then;
N*3.554*22=1 cm3
therefore N= 2.8*10-23 cm3
c) edge dimension= 3.04*10-8 m (cubic root of N)
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