The mass of a particular harpy eagle is twice that of a hunted parrot. Suppose t

Question

The mass of a particular harpy eagle is twice that of a hunted parrot. Suppose the parrot is flying north at 17.1 m/s, when the harpy eagle swoops down, grabs the parrot, and flies off. At the instant right before the attack, the harpy eagle is flying toward the parrot at an angle = 37.1° below the horizontal, and a speed of 31.3 m/s. What is the speed of the harpy eagle immediately after it catches its prey? Number m/s 31.3 m/s What is the magnitude of the angle, measured from horizontal, at which the harpy eagle is flying immediately after the strike? 17.1 m/s Number

Explanation / Answer

Apply the law of conservation of momentum, we get

m x 17.1i + 2m x (31.3cos37.1 i - 31.3sin37.1j) = 3 mv

Then the speed is,

v = 22.34i - 12.58 j m/s

Magnitude: v = speed = sqrt(22.34^2 + 12.58^2) = 25.64 m/s

angle =tan^-1(-12.58/22.34) = -29.38o

= 29.38o, below horizontal , clockwise direction

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