Potential Difference of a Capacitor A .380 uF (C1) and a 0.500 uF (C2) capacitor

Question

Potential Difference of a Capacitor

A .380 uF (C1) and a 0.500 uF (C2) capacitor are connected in series to a 9.00 V battery.

1)Calculate the potential difference across C1.

2) Calculate the potential difference across C2

3) Calculate the charge on C1.

4) Calculate the charge on C2.

5) Now assume that the two capacitors are connected in parallel. Calculate the voltage difference across C1.

6) Calculate the voltage difference across C2.

7) Calculate the charge on C1.

8) Calculate the charge on C2.

Explanations would be appreciated.

Explanation / Answer

a)

equivalent capacitance in series

1/Ceq =1/0.38 +1/0.5

Ceq=0.216 uF

Total Charge

Q=CeqV =0.216*9 =1.943 uC

Potential difference across C1 is

V1=Q/C1 =1.943/0.38=5.1 Volts

b)

Potential difference across C2 is

V2=Q/C2=1.943/0.5=3.9 Volts

c)

Charge on C1 is

Q1=1.943 uC

d)

Charge on C2 is

Q2=1.943 uC

e)

Potential difference across C1 is

V1=9 Volts

f)

Potential difference across C2 is

V2=9 Volts

g)

Charge on C1

Q1=C1V1=0.38*9 =3.42 uC

h)

Charge on C2 is

Q2=C2V2=0.5*9 =4.5 uC

equivalent capacitance

Ceq=0.5+0.38 =0.88 uF

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.