The following questions consider the electric field and forces produced by a pai

Question

The following questions consider the electric field and forces produced by a pair of charged particles that are held at fixed positions on the x-axis at x = +d and x = ?d.

A.If the charges are both positive and are equal in magnitude, in which direction does the electric field point at any point along the positive y ? axis?

1. the positive x direction

2. the negative x direction

3. the positive z direction

4. the positive y direction

5. the magnitude of the electric field is zero.

6. the negative y direction

7. the negative z direction

B.If the charges are both positive and are equal in magnitude, what is the direction of the electric field at the origin?

1. the positive x direction

2. the negative x direction

3. the positive z direction

4. the positive y direction

5. the magnitude of the electric field is zero.

6. the negative y direction

7. the negative z direction

C.If the charge at +d is positive and the one at ?d is negative but they are still equal in magnitude, in which direction does the electric field point at any point along the positive y ? axis?

1. the magnitude of the electric field is zero.

2. the negative z direction

3. the positive x direction

4. the negative y direction

5. the positive z direction

6. the positive y direction

7. the negative x direction

D.The charge at +d is positive q and the one at ?d is negative q. A third negative charge of ?q is placed at the origin. What is the magnitude and direction of the force on this third charge?

1. 2kq2 /d; the negative x direction

2. 2kq2 /d; the positive x direction

3. the magnitude of the force is zero.

4. 2kq/d2 ; the negative x direction

5. 2kq/d2 ; the positive x direction

6. 2kq2 /d2 ; the positive x direction

7. 2kq2 /d2 ; the negative x direction

E.The charge at +d is positive q and the one at ?d is negative q. A third positive charge of q is placed at y = 10d. What is the approximate magnitude of the force on this third charge?

1. (1/500)kq2 /d3

2. (1/100)kq2 /d2

3. 1/100)kq2 /d3

4. (1/500)kq2 /d2

5. (1/1000)kq2 /d3

Explanation / Answer

part a)

the electric field will be in positive y direction

part b)

electric field at origin is zero

part c)

electric field will be towards -ve x axis

part d)

2kq2/d in the -ve x direction

part e)

r2=101d2

F=21/2kq2/101d2

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