1. The Thanksgiving turkey (mT = 7.0 kg) is in the center of the table, on the t
ID: 1317245 • Letter: 1
Question
1. The Thanksgiving turkey (mT = 7.0 kg) is in the center of the table, on the tablecloth. The cat (m = 5.5 kg) attempts to investige the nice smell by leaping onto the hanging edge of the tablecloth. Assume that the coefficient of friction i between turkey and tablecloth is large, but the coefficient of friction between the tablecloth and the table under the turkey is only 0.4. What happens next? Is there enough friction between tablecloth and table that the cat can climb up the tablecloth? If not, what is the acceleration of the turkey? 2. A ?Vacuum Bazooka? accelerates a 2.5-gram ping-pong ball from rest to a speed of 300 m/s in a distance of 1.8 meters. What is the average force on the ping-pong ball? 3. A bouy of mass m bobbing in the ocean experiences a net force F = -pgAy. Ignoring why it experiences that force, or what all the constants pgA mean, would the buoy move with simple harmonic motion? If so, what would be the period of the buoy?s motion? 4. The position of a mass m at the end of a spring with spring constant k is given by y(t) = y0sin( square root (kt/m + psi)Explanation / Answer
normal reaction on turkey = mg = 7 x 9.8 = 68.6N
friction force between cloth & table = mu x N = .4 x 68.6 = 27.44 N
forc eacting due to hanging cat = mg = 5.5 x 9.8 = 53.9 N
assuming this system as a 2 mass system attached by a string passing over a pulley
53.9 - T = 5.5a..................1
T - friction = 7a
adding both
53.9 - 27.44 = [5.5+7]a
a = 2.11 m/s^2
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