Concurrent Forces For the following diagram: Force A and Force B act on the eye

Question

Concurrent Forces

For the following diagram: Force A and Force B act on the eye of the ring. To find the resultant force you must resolve each of the forces into their vertical and horizontal components. Assume both angles are in standard position.

Part A

Given Force A = 200 newtons and B = 450 newtons.

Find the vertical component of A.

I found Av to be 193 N

Part B

Given Force A = 200 newtons and B = 450 newtons.

Find the horizontal component of B.

Bh is 390 N

however I need help with these following parts

Part C

Given Force A = 200 newtons and B = 450 newtons.

Find the Magnitude and Direction of A + B, seperate by a comma. Direction measured clockwise from - x axis

Mag, angle =? Newton, Degree

Part D

Given Force A = 200 newtons and B = 450 newtons.

Find the magnitude of 2A-B

Mag = ?? Newton

Please help me!!

Explanation / Answer

Part A)

Vertical component of A = 200(sin 75) = 193 N

Part B)

Horizontal component of B = (450)(cos 30) = 390 N

Part C)

We need horizontal component of A and vertical component of B

Ax = (200)(cos 75) = 52 N

By = (450)(sin 30) = 225 N

The net x = 390 + 52 = 442 N

The net y = 193 + 225 = 418 N

The net of A + B is found from the Pythagorean Theorem

Net2 = (442)2 + (418)2

Net = 608 N

The angle is from the tangent function

tan(angle) = 418/442

angle = 43.4o

Thus the answer is 608 N at 43.4o

Part D)

The net x = 2(52) - 390 = -286 N

The net y = 2(193) - 225 = 161 N

The net...

Net2 = (286)2 + (161)2

Net = 328 N

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