A Bar Suspended by Two Vertical Strings The figure (Figure 1) shows a model of a

Question

A Bar Suspended by Two Vertical Strings

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 85.00kg and length L = 5.400m is supported by two vertical massless strings. String A is attached at a distance d = 1.600m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500kg is supported by the crane at a distance x = 5.200m from the left end of the bar.

Throughout this problem, positive torque is counterclockwise and use 9.807m/s2 for the magnitude of the acceleration due to gravity.

Part A

Find TA , the tension in string A.

Express your answer in newtons using four significant figures.

Part B

Find TB , the magnitude of the tension in string B.

Express your answer in newtons using four significant figures.

Explanation / Answer

Part A)

Start by placing the pivot point at B and solve by the sum of torques...

mgl = Ad

(3500)(9.807)(5.2) = (A)(1.6)

A = 1.116 X 105 N

Part B)

By the sum of forces...

1.116 X 105 = (B) + (3500)(9.807)

B = 7.723 X 104 N

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