A particle with a charge of 18.2 mC moves along the x -axis with a speed of 49.2

Question

A particle with a charge of 18.2 mC moves along the x-axis with a speed of 49.2 m/s. It enters a magnetic field given by vector B = 0.321 y(hat)+ 0.723 z(hat), in teslas.

a) Determine the magnitude of the magnetic force on the particle.
0.708 N

b) Determine the Cartesian components of the magnetic force on the particle (in units of N). Do not enter units, and enter the vector as comma-separated list! Example, if you think that the force vector has an x-component of 0.5 N and a z-component of 0.1 N, then enter: 0.5, 0, 0.1

Explanation / Answer

net magnitude of magnetic field is B^2 = Bx^2 +By^2

B^2 = 0.321^2 + 0.723^2

B^2 = 0.62577

B = 0.791 Tesla

now use magnetic force F = qvB

F = 0.0182 * 49.2 * 0.791

F = 0.708 N

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Fx = 0.0183 * 49.2 * 0.5 = 0.45 N

Fz = 0.0183 * 49.2 * 0.1 = 0.09 N

so answer is   0.45 , 0.09

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