A coil is made up of 36 square loops with the sides equal to 2.7 cm. The coil is

Question

A coil is made up of 36 square loops with the sides equal to 2.7 cm. The coil is placed in a uniform 350 mT magnetic field.

a) What is in Webers the magnetic flux through the coil if the magnetic field is parallel to the plane of the coil?

b) What is in Webers the magnetic flux through the coil when the magnetic field makes an angle of zero degrees with the normal to the coil (perpendicular to the plane of the coil)?

c) What is in Webers the magnetic flux through the coil when the magnetic field makes an angle of 180

Explanation / Answer

(a):

mag. flux = B.A cos(theta)

theta is angle between area vector and mag. field vector

area vector is always perpendicular to area

therefore

Mag. flux = 36* B.A* cos(90) = 0 Waber

(b):

Mag. flux = 368B.A* cos(0) = B*A Waber = 36*350*10^(-3)* (2.7^10^(-2))^2 = 91.8540*10^(-4) waber

(c):

Mag. flux = B.A* cos(180) = 36*B*A Waber = -36*350*10^(-3)* (2.7^10^(-2))^2 = -91.8540*10^(-4) waber

(d):

Mag. flux = B.A* cos(46) =36* B*A cos(46) Waber = 36*350*10^(-3)* (2.7^10^(-2))^2 = 63.807*10^(-4) waber

(e):

Mag. flux = B.A* cos(46) = B*A cos(46) Waber = 350*10^(-3)* (2.7^10^(-2))^2 = 1.7724*10^(-4) waber

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