A person with body resistance between his hands of 10k? accidentally grasps the

Question

A person with body resistance between his hands of 10k? accidentally grasps the terminals of a 14-kV power supply.

Part A

If the internal resistance of the power supply is 1800? , what is the current through the person's body?

Express your answer using two significant figures.

Part B

What is the power dissipated in his body?

Express your answer using two significant figures.

Part C

If the power supply is to be made safe by increasing its internal resistance, what should the internal resistance be for the maximum current in the above situation to be Imax=1.00mA or less?

Express your answer using two significant figures.

Explanation / Answer

a) total R = 10k + 2k = 12k
I = E/R = 14k/12k = 1.2 amps and that person is dead

b) power = VI = 14k x 1.2 = 17 kW

c) R = E/I = 14k/1ma = 14 M?
subtract the 10k and it's still 14 M? with 2 digit accuracy.

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