Question 9 In the figure, S is a small loudspeaker driven by an audio oscillator

Question

Question 9 In the figure, S is a small loudspeaker driven by an audio oscillator and amplifier, adjustable in frequency from 530 to 2500 Hz only. Tube D is a piece of cylindrical sheet-metal pipe 38.5cm long and open at both ends. (a) If the speed of sound in air is 344 m/s at the existing temperature, at how many frequencies will a resonance occur in the pipe when the frequency emitted by the speaker is varied from 530 Hz to 2500 Hz? (b) What is the lowest resonant frequency in the given interval?

Explanation / Answer

first you need to find out the frequency:
344 m/s / 2(0.385 m) = 446.753 s-1

(a)
you need to look at the 630 Hz to 2500 Hz
how many times of multiples of 446.753 can you get that is between 630 Hz to 2500 Hz?

so lets see:
446.753 x 4 = 1787 thats one
446.753 x 5 = 2233.77 thats two

so two multiples of 446.753 can fit between 630 and 2500 so the answer is two

(b)
lowest is 1787 Hz

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.