6:39 PM OO AT&T; LTE 85% session masteringphysics.com Problem 21.85 MasteringPhy

Question

6:39 PM OO AT&T; LTE 85% session masteringphysics.com Problem 21.85 MasteringPhysics Problem 21.85 The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 340 V, which charges a capacitor. The capacitor is then discharged through a flashlamp. The discharge takes ll us and the average power dissipated in the flashlamp is l .0x 105 W Part A What is the capacitance of the capacitor Express your answer to two significant figures and include the appropriate units. c Value Units Submit Give Up Continue

Explanation / Answer

Given that

The average power dissipated in the flash lamp is 1.0*105W

The discharge takes a time period of (deltat) =11us =11*10-6s

We know that

Pavg =DeltaE/Deltat

Then DeltaE =Pavg*Deltat =(1.0*105W)(11*10-6s) =1.1J

We know that energy stored in acapacitor is given by

E =(1/2)CV2

then we get that by taking voltage is 3V

The capacitance of a capacitor is C =2E/V2 =2*1.1/(3)2 =0.244F

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