Part A Compute the equivalent resistance of the network in the figure (Figure 1)

Q: Part A Compute the equivalent resistance of the network in the figure (Figure 1)

for top R1 = 1+3 = 4 for lower part R2 = 7+5 = 12 Req = (4*12)/(4+12) = 3

ID: 1320534 • Letter: P

Question

Part A

Compute the equivalent resistance of the network in the figure (Figure 1) The battery has negligible internal resistance.

Part B

Find the current in 1.00? resistor.

Part C

Find the current in 3.00? resistor.

Part D

Find the current in 5.00? resistor.

Part E

Find the current in 7.00? resistor.

Part A Compute the equivalent resistance of the network in the figure (Figure 1) The battery has negligible internal resistance. Part B Find the current in 1.00? resistor. Part C Find the current in 3.00? resistor. Part D Find the current in 5.00? resistor. Part E Find the current in 7.00? resistor.

Explanation / Answer

for top R1 = 1+3 = 4

for lower part R2 = 7+5 = 12

Req = (4*12)/(4+12) = 3 <-------answer

Itot = e/Req = 48/3 = 16 A

partB)

I1 = Itot*R2/(R1+R2) = (16*12)/(4+12) = 12 A <---------asnwer

part C)

1 & 3 are inseries so the same through 3 i.e 12 A <---------asnwer

partC)

I2 = Itot-I1 = 16- 12 = 4 A <---------asnwer

part C)

5 & 7 are inseries so the same through 7 ohms is 4 A <---------asnwer

Navigate

Part A Compute the equivalent resistance of the network in (Figure 1) . Express

Part A Compute the impedance of a series R-L-C circuit at angular frequencies of

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.

Part A Compute the equivalent resistance of the network in the figure (Figure 1)

Question

Explanation / Answer

Related Questions

Navigate