Part A Compute the impedance of a series R-L-C circuit at angular frequencies of

Question

Part A

Compute the impedance of a series R-L-C circuit at angular frequencies of ? 1= 1000rad/s , ?2= 760rad/s and ?3= 490rad/s . Take R = 200? , L = 0.940H and C = 1.70?F .

Enter your answers in ? as three numbers separated with commas. Z1, Z2, Z3   

Part B Describe how the current amplitude varies as the angular frequency of the source is slowly reduced from 1000rad/s to 490rad/s .

A.Amplitude is always constant.

B. Amplitude decreases.

C. Amplitude increases.

D. First amplitude increases next it decreases.

E. First amplitude decreases next it increases.

Part C What is the phase angle of the source voltage with respect to the current when ? = 1000 rad/s?

Explanation / Answer

Z1 = sqrt( R^2 + ( ( wL) - (1/wC))^2) = sqrt( 200^2 + ( ( 1000*0.94) - (1/(1000*1.7 *(10^-6))))^2) = 404.646 ohms
Z2 = sqrt( R^2 + ( ( wL) - (1/wC))^2) = sqrt( 200^2 + ( ( 760*0.94) - (1/(760*1.7 *(10^-6))))^2) = 208.689 ohms
Z3 = sqrt( R^2 + ( ( wL) - (1/wC))^2) = sqrt( 200^2 + ( ( 490*0.94) - (1/(490*1.7 *(10^-6))))^2) = 766.435 ohms
B)
D. First amplitude increases next it decreases.
C)
phase angle = atan ((( wL) - (1/wC))/R) = atan((( 1000*0.94) - (1/(1000 * 1.7 * (10^-6))))/200) = 60.379 degrees

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