Part A Compute the impedance of a series R-L-C circuit at angular frequencies of

Question

Part A Compute the impedance of a series R-L-C circuit at angular frequencies of %u03C91= 1000rad/s , %u03C92= 705rad/s and %u03C93= 520rad/s . Take R = 185%u03A9 , L = 0.950H and C = 2.50%u03BCF . Enter your answers as three numbers separated with commas. Part C What is the phase angle of the source voltage with respect to the current when %u03C9 = 1000 rad/s? Part A Compute the impedance of a series R-L-C circuit at angular frequencies of %u03C91= 1000rad/s , %u03C92= 705rad/s and %u03C93= 520rad/s . Take R = 185%u03A9 , L = 0.950H and C = 2.50%u03BCF . Enter your answers as three numbers separated with commas. Part C What is the phase angle of the source voltage with respect to the current when %u03C9 = 1000 rad/s? Part C What is the phase angle of the source voltage with respect to the current when %u03C9 = 1000 rad/s?

Explanation / Answer

1000 rad/s==>R=185 ohms==>L=0.95 H==>C=2.5 uF

XL=1000*0.95=950 ohms==>XC=1/(1000*2.5E-6)=400 ohms

Z=sqrt(R^2+(XL-XC)^2)=580.28 ohms for 1000 rad/s==>XL=705*0.95=669.75 ohms

XC=1/(705*2.5E-6)=567.4 ohms==>Z=sqrt(R^2+(XL-XC)^2)=211.44 ohms

XL=520*0.95=494 ohms==>1/(520*2.5E-6)=769 23 ohms

Z=sqrt(R^2+(XL-XC)^2)=331.63 ohms

Part A) 580.28, 211.44, 331.63 ohms

Part C) arctan((XL-XC)/R)=28.95 degrees

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