(a) 3.33, 0, 18.8, 20.9, 23, 65.8, 0.0477, 65.8 3.14, 0.150, 10.5 are the option
ID: 1320735 • Letter: #
Question
(a) 3.33, 0, 18.8, 20.9, 23, 65.8, 0.0477, 65.8 3.14, 0.150, 10.5 are the options specify rad/s or m/s
(b) 3.46, 3.14, 0, 65.8, 20.9, 1.57, 0.500, 65.8, 20.9 are the options specify units.
(c) 55.9, 10.5, 20.9, 65.8, 0.500, 0, 71.1 are the opitons specify units.
(d) 69.8, 65.8, 3.14, 0, 73.7, 57.2, are the options specify the units.
(e) 0, 65.8, 74.4, 82.2, 60.5, 3.14, 57.2 are the opitons specify the units.
The graph below gives the position x vs. t for a spot on rim of a rotating wheel. From the graph determine the following quantities: (a) The angular speed w: (b) The speed of the spot V: (c) The magnitude of centripetal acceleration of the spot ac: (d) The magnitude of angular acceleration a: (e) The magnitude of tangential acceleration of the spot at: (a) 3.33, 0, 18.8, 20.9, 23, 65.8, 0.0477, 65.8 3.14, 0.150, 10.5 are the options specify rad/s or m/s (b) 3.46, 3.14, 0, 65.8, 20.9, 1.57, 0.500, 65.8, 20.9 are the options specify units. (c) 55.9, 10.5, 20.9, 65.8, 0.500, 0, 71.1 are the opitons specify units. (d) 69.8, 65.8, 3.14, 0, 73.7, 57.2, are the options specify the units. (e) 0, 65.8, 74.4, 82.2, 60.5, 3.14, 57.2 are the opitons specify the units.Explanation / Answer
from the graph Time period ( time taken by 1 full pattern)
= 0.3 - 0 = 0.3 sec
f = 1/T
and w = 2 x pi x f = 2 xpi / 0.3 = 20.94 rad/s .......Ans
b) v = Aw = 0.15 x 20.94 = 3.14 m/s
c) a_c = w^2A = 65.8 m/s2
d) alpha = 0
e) a_t =0
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