Three resistors with resistances R 1 = 20.0 ohms, R 2 = 49.0 ohms and R 3 = 85.0

Question

Three resistors with resistances R1 = 20.0 ohms, R2 = 49.0 ohms and R3 = 85.0 ohms are placed along the sides of a triangle as shown in circuit 1. What are the values of the resistances Ra, Rb and Rc that would provide an equivalent circuit as arranged in circuit 2?

Three resistors with resistances R1 = 20.0 ohms, R2 = 49.0 ohms and R3 = 85.0 ohms are placed along the sides of a triangle as shown in circuit 1. What are the values of the resistances Ra, Rb and Rc that would provide an equivalent circuit as arranged in circuit 2?

Explanation / Answer

Ra=R1R3/(R1+R2+R3)

Ra=20*85/(20+49+85)

Ra=11.0389 ohm

Rb=R1R2/(R1+R2+R3)

Rb=20*49/(20+49+85)

Rb=6.3636 ohm

Rc=R2R3/(R1+R2+R3)

Rc=49*85/(20+49+85)

Rc=27.045 ohm

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