Given the circuit below. R is 1090Ohms , C1 is 59 ? F , C2 is 196 ? F , C3 is 20

Question

Given the circuit below. R is 1090Ohms , C1 is 59?F , C2 is 196?F , C3 is 200?F , C4 is 134?F , and E is 36.5V .

Part A

What is the total capacitance of this circuit?

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Part B

What is the total resistance of this circuit?

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Part C

What is the time constant for this circuit?

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Part D

What is the charge at time 0.544s , when the capacitor is charging up?

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Part E

What time is the charge 2.21?10?3C , when the capacitor is charging up?

C_{total} = F Given the circuit below. R is 1090Ohms , C1 is 59?F , C2 is 196?F , C3 is 200?F , C4 is 134?F , and E is 36.5V . Part A What is the total capacitance of this circuit? C_{total} = F SubmitHintsMy AnswersGive UpReview Part Part B What is the total resistance of this circuit? R_{total} = Omega SubmitMy AnswersGive Up Part C What is the time constant for this circuit? tau = s SubmitMy AnswersGive Up Part D What is the charge at time 0.544s , when the capacitor is charging up? q = C SubmitMy AnswersGive Up Part E What time is the charge 2.21½10?3C , when the capacitor is charging up? t = s SubmitMy AnswersGive Up

Explanation / Answer

Here ,

Here,
In parallel for capacitor ,
Ceq = c1 + C2
and in series ,

1/ Ceq = 1/c1 + 1/c2 + ...

A) as C1 , C2 and C3 are in series

1/C5 = 1/50 + 1/196 + 1/200

C5 = 33.2 uF

now , C5 and C4 are in parallel,

Ceq = 33.2 + 134

Ceq = 167.2 uF

the total capacitance is 167.2 uF

B)

R = 1090 Ohm

C)

Time constant , T = RC

T = 1090 * 167.2 *10^-6

T = 0.1822 s

the time costant is 0.1822 s

D)

Q = 36.5 * 167.2 *(1 - e^(-0.544/.182))

Q = 5794.6 uC

Charge is 5.794 *10^-3 C

E)

2.21 *10^-3 = 36.5 * 167.2*10^-6 *(1 - e^(-t/.1822))

t = 0.082 s

time is 0.082 s

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