An electric field is constant at every point on a square surface that is 0.80 m

Question

An electric field is constant at every point on a square surface that is 0.80 m on a side. This field has a magnitude of 5.3 N/C and is oriented at an angle of 35 with respect to the surface, as the drawing shows. Calculate the electric flux ?E passing through the surface.

An electric field is constant at every point on a square surface that is 0.80 m on a side. This field has a magnitude of 5.3 N/C and is oriented at an angle of 35½ with respect to the surface, as the drawing shows. Calculate the electric flux ?E passing through the surface.

Explanation / Answer

d?E= E*dA

Integrating both sides we obtain

?E = E*A since E is a constant it can be pulled outside of the integrand. The integral of dA is just A



But since the orientation is angled at 35 degrees, the flux only accounts for any electric field lines that go through a surface perpendicularly. That means that our equation needs to account for this

?E= E*A*sin(35) =1.945 Vm

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