winging a mass on a string requires string tension, and the mass will travel off

Question

winging a mass on a string requires string tension, and the mass will travel off in a tangential straight line if the string breaks. The centripetalacceleration can be derived for the case of circular motion since the curved path at any point can be extended to a circle.

winging a mass on a string requires string tension, and the mass will travel off in a tangential straight line if the string breaks. The centripetalacceleration can be derived for the case of circular motion since the curved path at any point can be extended to a circle.

Explanation / Answer

A. Centripetal force = m*v2 /r =1730 * 46.482/2000 = 1.868 KN

B. 1868.74 = u* M* g

u = 0.11

C.V = 46.48 m/s

So, W= V/r = 38.7333 rad/sec

D. total dist. = circumference = 2 *3.14* 2000= 12566.37 m

in one rotation dist. covered by tire= 2*3.14*1.2 =7.536 m

total rev. = 12566.37/7.536=1667.511 = 1668 approx

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