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The drawing shows a collision between two small balls. Ball 1 has a mass of 130

ID: 1322759 • Letter: T

Question

The drawing shows a collision between two small balls. Ball 1 has a mass of 130 g and is moving along the x axis with a velocity of 4.00 m/s. It makes a collision with ball 2, which has a mass of 195 g and is initially at rest. After the collision, the two balls fly apart with angles as shown in the figure below (? = 42 and ? = 58). What is the magnitude of the velocity of ball 2 after the collision?

The drawing shows a collision between two small balls. Ball 1 has a mass of 130 g and is moving along the x axis with a velocity of 4.00 m/s. It makes a collision with ball 2, which has a mass of 195 g and is initially at rest. After the collision, the two balls fly apart with angles as shown in the figure below (? = 42 and ? = 58). What is the magnitude of the velocity of ball 2 after the collision?

Explanation / Answer

Given that

Ball 1 has a mass of (m1) = 130 g and is moving along the x axis

The intial velocity of the ball 1 is (u1) = 4.00 m/s.

It makes a collision with ball 2, which has a mass of (m2) = 195 g and is initially at rest (u2) =0

Now the components along the x-axis becomes is

              m1u1 =m1v1costheta1+m2v2costheta2------(!)

along the y-axis

                0 = -m1v1sintheta1+m2v2sintheta2...........(2)

From second equation we get v1/v2 =1.901 then v1 =1.901v2......(3)

Now substitute the equation (3) in equation (1) we get

m1u1 =m1v1costheta1+m2v2costheta2

130*10-3*4 =130*10-3*1.901v2cos(42)+195*10-3*v2*cos(58)

520 =(183.65+103.33)v2

The magnitude of the velocity of ball 2 after the collision

v2 =520/286.98 =1.811m/s

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