Molecules of carbon monoxide are permanent electric dipoles due to unequal shari

Question

Molecules of carbon monoxide are permanent electric dipoles due to unequal sharing of electrons between the carbon and oxygen atoms. (Figure 1) shows the distance and charges. Suppose a carbon monoxide molecule with a horizontal axis is in a vertical electric field of strength 15000 N/C .

What is the magnitude of the net force on the molecule?

What is the magnitude of the torque on the molecule?

Molecules of carbon monoxide are permanent electric dipoles due to unequal sharing of electrons between the carbon and oxygen atoms. (Figure 1) shows the distance and charges. Suppose a carbon monoxide molecule with a horizontal axis is in a vertical electric field of strength 15000 N/C . What is the magnitude of the net force on the molecule? What is the magnitude of the torque on the molecule?

Explanation / Answer

a)

a)Magnitude of force =equal and opposite due to vertical electric field=0

F =0

b)

First convert nm to meters which becomes 1.1*10^-10.

Torque= p*E(electric field)

Remember p= q(charge)* L(distance)

p= (3.4*10^-21 C) * (1.1*10^-10) = 3.74*10^-31 plug in back to Torque equation

Torque= (3.74*10^-31)*(15000) =5.61*10^-27 N*m

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