a) What angle would the beam that leaves the glass surface make with the normal

Question

a) What angle would the beam that leaves the glass surface make with the normal to the glass surface? Provide the answer in degrees.

b) How far vertically (d) is the point at which the beam leaves the glass surface from the point at which the beam entered the glass? Provide the answer in mm.

A beam of light makes an angle of ?i = 18.0? with the normal of a slab of transparent material of t = 1.10 mm - thickness. The index of refraction of the glass is n2 = 1.28. a) What angle would the beam that leaves the glass surface make with the normal to the glass surface? Provide the answer in degrees. b) How far vertically (d) is the point at which the beam leaves the glass surface from the point at which the beam entered the glass? Provide the answer in mm.

Explanation / Answer

n? sin theta1 = n2 sin theta2

sin 18 = 1.28 * sin theta

theta = 13.97 deg

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Distance traveled by the beam

d = 1.10 mm / cos 13.97

= 1.13 mm

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