used in the laboratory. In the calorimeter there is 150. g of water, initially a

Question

used in the laboratory. In the calorimeter there is 150. g of water, initially at 18.0°C. What is the final temperature of the water and beads? Assume that the 20.0 g stirrer is made of stainless steel with a specific heat of 0.120 cal/(g°C). The calorimeter is made from two aluminum cups with an insulator in between. Suppose that the outside one has a mass of 80.0 grams and the inner one has a mass of 40.0 grams. Look at the diagram in the laboratory manual to see which part, if any or all, of the calorimeter mass needs to be included in the calculation

Explanation / Answer

here,

let the final temperature is Tf

heat lost by glass beads = heat gain by water + heat gain by stirrer + heat gain by inner cup of aluminuim

100 * (120 - Tf) * 0.84 = 120 * 4.186 *(Tf - 18) + 0.215 * 40 * (Tf - 18) + 20 * (Tf -18) * 0.120 * 4.186

Tf = 18 degree C

the final temprature of water and beads is 18 degree C

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