5. A particle\'s position is given by: R (5t _ 2t2 + 10) + ( 10t-40th-6)J vector

Question

5. A particle's position is given by: R (5t _ 2t2 + 10) + ( 10t-40th-6)J vectors (R, i, and j), and t is in seconds, R is in meters where the bold, underlined quantities are vectors (R. i.andj, and is in seconds R is in meters. a. What is the initial position of the object? Give your answer in unit vector AND polar b. What is the particle's average velocity between c. What is the particle's instantaneous velocity at d. Is the particle's acceleration constant? Prove notation. Include a diagram. t = l and t = 3 seconds? t-5 seconds? your answer

Explanation / Answer

a)

for initial position let's find R at t=0

=> R= 10i -6j

b)

V= dR/dt = (5-4t)i + (10 -20/t1/2 ) j

V(1) = i + -10j

V(3) = -7i - 1.56j

V avergare = (V(3) - V(1))/(3-1)

V average =( -8i -11.56j)2 = -4i - 5.78j m/s

c)

V= dR/dt = (5-4t)i + (10 -20/t1/2 ) j

V(5) = -15i + 1.04 m/s

d)

a = dV/dt = (d/dt)(5-4t)i + (10 -20/t1/2 ) j

a= (-4i + 10/t3/2 ) m/s^2

so a is not constant

Related Questions

Navigate

• Browse (All)
• Browse 5
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.