Problem 1 The system of five cables is used to support the pipe as shown. Assume

Question

Problem 1 The system of five cables is used to support the pipe as shown. Assume the system is in equilibrium. (a) 1f the weight of the pipe is W, determine the force in each cable for equilibrium in terms of W. (b) If each cable can support a maximum tension of 500 N, determine the maximum weight of pipe that can be supported. Problem 2 The blocks are in equilibrium as shown. The mass of block A is 40 kg, and the mass of block B is 60 kg. The spring is horizontal with spring constant 1000 N/m. Neglect frictions.. (a) Draw the free-body diagrams of blocks A and B. (b) Determine the force In the spring. (c) If the spring has an unstreched length of 0.5 m, what is its current length at this equilibrium position?

Explanation / Answer

problem 1)when object is in equilbrium net force on it is equal to zero.use this concept we have to solve above problem.

a) Tsin(60)=W

In AE cable, Tcos(60)=tension(T1)

Tension in AB cable is sqrt(w^2=T1^2)

Tension in BD cable is 5N

Tension in CB cable is 4N

b) Tsin(60)=W

each cable force is 500N

w=500*1.732N

problem 2)i will give hint u have to folow in that way

mg is actimg down wards divide it ino two components along x and y axis.normal reaction is perpenducular to inclined and object suface,on OBJECT A normal recation from OBJECT B and spring force also.

b) F= Kx formula

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