An artillery shell is fired with an initial velocity of 300 m/s at 61.5 degrees

Question

An artillery shell is fired with an initial velocity of 300 m/s at 61.5 degrees above the horizontal. To clear an avalanche, it explodes on a mountainside 43.5 s after firing. What are the x and y coordinates of the shell where it explodes, relative to its firing point? An artillery shell is fired with an initial velocity of 300 m/s at 61.5 degrees above the horizontal. To clear an avalanche, it explodes on a mountainside 43.5 s after firing. What are the x and y coordinates of the shell where it explodes, relative to its firing point?

Explanation / Answer

Here ,

initial speed , v0 = 300 m/s

theta = 61.5 degree

after , t = 43.5 s

x - coordinate = v0 * cos(theta) * t

x - coordinate = 300 * cos(61.5) * 43.5

x - coordinate = 6226.9 m

for the y -coordinate

y -coordinate = u * t - 0.5 at^2

y -coordinate = 300 * sin(61.5) * 43.5 - 0.5 * 9.8 * 43.5^2

y -coordinate = 2197 m

the corrdinates of the projectile afyer 43.5 s is (6226.9 m , 2197 m )

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.