What is the path-length-difference for waves traveling from the two speakers to

ID: 1328399 • Letter: W

Question

What is the path-length-difference for waves traveling from the two speakers to point A?: answered 1.28

What is the longest wavelength for which there is a maximum signal at A due to constructive interference?

What is the lowest frequency for which there is a maximum signal at A due to constructive interference?

answered: 2.68 x 102 Hz

What is the second lowest frequency for which there is a maximum signal?

What is the lowest frequency for which there is a minimum signal due to destructive interference?

To calculate longest wavelength for which there is maximum signal

n(wavelength ) = path difference

For max wavelength n = 1

wavelength = path difference = 1.28m

To calculate second lowest frequency, we use n=2

n(wavelength) = path difference

2(wavelength) = 1.28

wavelength = 0.64m

frequency = wave speed/wavelength = 343/0.64 = 535.9 Hz

When there is destructive interference

n(wavelength)/2 = path difference

we get lowest frequency for n=1

(1)(wavelength)/2 = 1.28

wavelength = 1.28 x 2 = 2.56 m

frequency = wave speed/wavelength = 343/2.56 = 133.98Hz

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