A toboggan approaches a snowy hill moving at 14.3 m/s . The coefficients of stat

Question

A toboggan approaches a snowy hill moving at 14.3 m/s . The coefficients of static and kinetic friction between the snow and the toboggan are 0.400 and 0.300, respectively, and the hill slopes upward at 42.0 above the horizontal.

Part A

Find the acceleration of the toboggan as it is going up the hill.

Assume +x axis directed up the hill.

2.18

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Part B

Find the acceleration of the toboggan after it has reached its highest point and is sliding down the hill.

Assume +x axis directed up the hill.

A toboggan approaches a snowy hill moving at 14.3 m/s . The coefficients of static and kinetic friction between the snow and the toboggan are 0.400 and 0.300, respectively, and the hill slopes upward at 42.0 above the horizontal.

Part A

Find the acceleration of the toboggan as it is going up the hill.

Assume +x axis directed up the hill.

ax =

2.18

  m/s2  

SubmitMy AnswersGive Up

Incorrect; Try Again; 4 attempts remaining

Part B

Find the acceleration of the toboggan after it has reached its highest point and is sliding down the hill.

Assume +x axis directed up the hill.

ax =   m/s2  

Explanation / Answer

part A)

let the acceleration of the tobaggan is a

a = - g * sin(theta) + uk * g* cos(theta)

a = - 9.8 *(sin(42) + 0.30 * cos(42))

a = - 8.741 m/s^2

the acceleration of the toboggan as it is going up the hill is - 8.741 m/s^2

part B)

when the toabaggan is going down the hill

acceleration = - g * sin(theta) + uk * g* cos(theta)

a = - 9.8 *(sin(42) - 0.30 * cos(42))

a = - 4.37 m/s^2

the acceleration of the toboggan after it has reached its highest point and is sliding down the hill is - 4.37 m/s^2

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