A toboggan approaches a snowy hill moving at 13.7 m / s . The coefficients of st
ID: 2137961 • Letter: A
Question
A toboggan approaches a snowy hill moving at 13.7m/s . The coefficients of static and kinetic friction between the snow and the toboggan are 0.410 and 0.310, respectively, and the hill slopes upward at 40.0? above the horizontal.Part A Find the acceleration of the toboggan as it is going up the hill. Assume +x axis directed up the hill.
Part B
Find the acceleration of the toboggan after it has reached its highest point and is sliding down the hill. Assume +x axis directed up the hill. A toboggan approaches a snowy hill moving at 13.7m/s . The coefficients of static and kinetic friction between the snow and the toboggan are 0.410 and 0.310, respectively, and the hill slopes upward at 40.0? above the horizontal.
Part A Find the acceleration of the toboggan as it is going up the hill. Assume +x axis directed up the hill.
Part B
Find the acceleration of the toboggan after it has reached its highest point and is sliding down the hill. Assume +x axis directed up the hill. Part A Find the acceleration of the toboggan as it is going up the hill. Assume +x axis directed up the hill.
Part B
Find the acceleration of the toboggan after it has reached its highest point and is sliding down the hill. Assume +x axis directed up the hill.
Explanation / Answer
when it is ascending the hill its acceleration will be
a = g ( sin40 +u cos40) , where 'u' is coefficient of kinetic friction
= 8.5626 m/sec^2 ( after using the values and simplifying)
when it is sliding down, acceleration will be given as
a = g (sin40 - u cos40 ) = 3.972 m/sec^2
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