a block of mass 30.0kg slides down an incline of 40.0 degrees. If the coefficien

Question

a block of mass 30.0kg slides down an incline of 40.0 degrees. If the coefficient of kinetic friction between the block and the incline is 0.300, find A) the acceleration of the block as it travels down the incline. B) the frictional force acting on the block. a block of mass 30.0kg slides down an incline of 40.0 degrees. If the coefficient of kinetic friction between the block and the incline is 0.300, find A) the acceleration of the block as it travels down the incline. B) the frictional force acting on the block. a block of mass 30.0kg slides down an incline of 40.0 degrees. If the coefficient of kinetic friction between the block and the incline is 0.300, find A) the acceleration of the block as it travels down the incline. B) the frictional force acting on the block.

Explanation / Answer

F = ma
mg sin() - umg cos() = ma
a = g (sin() - u cos())
a = (9.8 m/s^2) (sin(40) - 0.300cos(40))
= 4.04 m/s^2

the frictional force = the coefficient times the normal force, you have

Ff = 0.300*30*9.8*cos40 = 67.56 N

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