A force of 27.0 N is directed downward perpendicular to the stick at Point G. Wh

Question

A force of 27.0 N is directed downward perpendicular to the stick at Point G. What is the torque from this force?

A force of 16.0 N is directed upward perpendicular to the stick at Point B. What is the torque from this force?

A force of 37.0 N is directed upward at angle 36.2° to the right of the perpendicular to the stick at Point C. What is the torque from this force?

A force of 27.0 N is applying horizontally to the right at C. What is the torque from this force?

Two forces are applied simultaneously to the stick. A force of 22.0 N is directed upward perpendicular to the stick at Point K and a force of 16.0 N is directed upward perpendicular to the stick at Point B. What is the net torque from these two forces?

Explanation / Answer

Torque T = r*F*sin(90) = 6*0.091*22 = 12.012 N-m

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Torque T = -3*0.091*27 = -7.371 N-m

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Torque T = -3*0.091*16 = -4.368 N-m

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Torque T = 7*0.091*37*cos(36.2) = 19.01 N-m

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Torque T = 0N-m

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net torque is Tnet = (6*0.091*22)-(3*0.091*16) = 7.644 N-m

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