When two charges ( q 1 and q 2 ) are held a distance d apart from each other, ea

Question

When two charges (q1 and q2) are held a distance d apart from each other, each exerts a force of magnitude F on the other.
(a) If one of the charge's magnitude is doubled and the distance between the charges is increased by a factor of 5, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)?
F
(b) If both of the charge's magnitudes are doubled and the distance between the charges is increased by a factor of 5, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)?
F

Please explain how you got your answer I am very confused by how to get the correct answer

Explanation / Answer

F = kq1q2/r2

a) The new magnitude will be (2/25)F. The doubled of the charge linearly increases the force, whereas the force is proportional to the inverse of the square of the distance - affecting it by a factor of 1/25.

b) The new magnitude will be (4/25)F. The doubled of the both charges

linearly increases the force, whereas the force is proportional to the inverse of the square of the distance - affecting it by a factor of 1/25.

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