When two charges ( q 1 and q 2 ) are held a distance d apart from each other, ea

Question

When two charges (q1 and q2) are held a distance d apart from each other, each exerts a force of magnitude F on the other.
(a) If one of the charge's magnitude is quadrupled and the distance between the charges is increased by a factor of 6, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)?
     F
(b) If both of the charge's magnitudes are quadrupled and the distance between the charges is increased by a factor of 6, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)?

Explanation / Answer

F = K * Q1 *Q2 / d^2

now F is directly proportional to Q1 and Q2

and inversely to d^2

(a)

=>new Q1 = 4 *Q1

and new D = 6d

=>F(new) = F * 4 / 6^2 = F*4/36 = F*1 / 9 ans...

(b)

=> new Q1 = 4*Q1

new Q2 = 4*Q2

new D =6d

=> F(new) = F *4*4/6^2 = 16*F / 36 = F*4 / 9 ans...

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