When two charges ( q 1 and q 2 ) are held a distance d apart from each other, ea

Question

When two charges (q1 and q2) are held a distance d apart from each other, each exerts a force of magnitude F on the other.
(a) If one of the charge's magnitude is quadrupled and the distance between the charges is increased by a factor of 6, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)?
     F
(b) If both of the charge's magnitudes are quadrupled and the distance between the charges is increased by a factor of 6, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)?
     F

Explanation / Answer

a) F ~ q and ~ 1/r^2; so F' = F (4)*(1/36) = F/9 ANS.

b) F' = F (4*4)/36 = 4F/9 ANS.

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