When two charges (q1 and q2) are held a distance d apart from each other, each e

Question

When two charges (q1 and q2) are held a distance d apart from each other, each exerts a force of magnitude F on the other.
(a) If one of the charge's magnitude is doubled and the distance between the charges is increased by a factor of 8, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)?

(b) If both of the charge's magnitudes are doubled and the distance between the charges is increased by a factor of 8, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)?

Explanation / Answer

F = kqq/d^2 F is directly prop. to q/d^2 a. (2/8^2)F = (2/64)F b. (2 x 2)/(8^2) = (4/64)F

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