When two charges (q1 and q2) are held a distance d apart from each other, each e

Question

When two charges (q1 and q2) are held a distance d apart from each other, each exerts a force of magnitude F on the other. (a) If one of the charge's magnitude is tripled and the distance between the charges is increased by a factor of 7, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)? F (b) If both of the charge's magnitudes are tripled and the distance between the charges is increased by a factor of 7, what will be the new magnitude of the force exerted by one charge on the other (as a multiple of F)? F

Explanation / Answer

a) F1=k3q1q2/(7r)^2

=3/49(kq1q2/r^2 =3/49F

b) F2=k3q13q2/(7r)^2 =9/49F

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