The potential energy of a ball due to its height above the ground isgiven by the
ID: 1332392 • Letter: T
Question
The potential energy of a ball due to its height above the ground isgiven by the equation 1
PE =mgh
where is the mass of the ball (1.5 Kg), g is gravitational acceleration(9.8m/s^2), and h is the height of the ball above the surface of the earth (m).The kinetic energy is given by
KE =1/2mv^2
where v is the velocity of the ball (m/s). Assume that a ball is initiallystationary at height of 100 m. when the ball is released, it will start to fall.Calculate PE, KE and the total energy (PE + KE) of the ball at 10-m increments as it falls form its initial position. Create a table having theformat shown below
Table of PE,KE, and Total Energy vs Height
Height(m) PE(J) KE(J) (PE+KE) (J) ==================================================== 100.0 1471.5 0.0 1471.5
90.0 1324.4 147.2 1471.5
80.0 1177.2 294.3 1471.5
70.0 1030.1 441.4 1471.5
60.0 882.9 588.6 1471.5
50.0 735.8 735.8 1471.5
Note: the ball velocity at given height, h_0 , can be calculated by v=sqrt(2gh_0)
Explanation / Answer
Potential energy:
PE = mgh
Kinetic energy:
KE= 1/2mv2
As ball falls from maximum height, the potential energy would convert in to kinetic energy, but total energy is constant.
The decrease in potential energy is equal to increase in kinetic energy. But, total energy is constant.
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Height(m) PE(J) KE(J) (PE+KE) (J)
====================================================
Height PE KE Total energy
100.0 1470 0.0 1470
90.0 1323 147 1470
80.0 1176 294 1470
70.0 1029 441 1470
60.0 882 588 1470
50.0 735 735 1470
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