1.QUESTION If the ball is thrown at half the given speed, then it will land: A.)

Question

1.QUESTION If the ball is thrown at half the given speed, then it will land:

A.)more than half as far from the building. B.)less than half as far from the building. C)half as far from the building. D.)farther from the building than before. WHICH ONE? A,B,C,D

2. Use the worked example above to help you solve this problem. A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with an initial speed of 15.0 m/s. The point of release is h = 43.0 m above the ground.

(a) How long does it take for the ball to hit the ground?_______s

(b) Find the ball's speed at impact.________m/s

(c) Find the horizontal range of the ball.______m

EXERCISE Suppose the ball is thrown from the same height as in the PRACTICE IT problem at an angle of 31.0°below the horizontal. If it strikes the ground 44.6 m away, find the following. (Hint: For part (a), use the equation for the x-displacement to eliminate v0t from the equation for the y-displacement.)

(a) the time of flight_______s

(b) the initial speed_______m/s

(c) the speed and angle of the velocity vector with respect to the horizontal at impact

speed_______m/s

angle________° below the horizontal

Explanation / Answer

1)A more than half as far srom the building

2)we can use these formulas to solve it

H=-usin*t+(1/2)gt^2

43=-15sin30t+(1/2)*9.8*t^2

from it find time(t)value

for finding ball's speed

V=sqrt(Vx^2+Vy^2)

first find Vx=ucos* ,Vy=usin*-gt

Range=x*time of flight

R=x*T

EXERCISE

we can use these formulas to solve it

H=usin*t+(1/2)gt^2

here we can use for finding time of flight

Horizonal range=ucos*T

T=Horizonal range/ucos*

initial speed from this formula   H=usin*t+(1/2)gt^2

for finding ball's speed

V=sqrt(Vx^2+Vy^2)

first find Vx=ucos* ,Vy=usin*+gt

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