After a rockslide, three large boulders of mass m_1 = 528 kg, m_2 = 838 kg and m

Question

After a rockslide, three large boulders of mass m_1 = 528 kg, m_2 = 838 kg and m_3 = 311 kg block a busy highway through the mountains The rocks are side by side blocking the road and lined up from left to right in the order m_1, m_2, m_3. A bulldozer is used to slide the rocks off the road; the bulldozer applies a constant force to the left side of m_1. Assuming the rocks are all in contact and the road is a flat frictionless surface, what force, F_A, must be applied to mi to slowly accelerate the group of rocks from the road at 0.100 m/s^2? Use the value found above for F_A to find the force, F_12, exerted by the first rock of mass 528 kg on the middle rock of 838 kg.

Explanation / Answer

Here ,

let the force is FA

total mass , m = m1 + m2 + m3

m = 528 + 838 + 311

m = 1677 Kg

acceleration , a = 0.1 m/s^2

FA = m* a

FA = 1677 * 0.1

FA = 167.7 N

the force FA is 167.7 N

for the force F12

FA - F12 = m1 * a

167.7 - F12 = 528 * 0.1

F12 = 115 N

the force between F12 is 115 N

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