A unit of volume of water that engineers often use is the acre-foot, which equal

Question

A unit of volume of water that engineers often use is the acre-foot, which equals the volume of water that will cover an acre of land to a foot depth. If a town that is 14.3 mi^2 recieves 2 inches of rain in 4 hours, what volume of water, in acre-feet, fell on the town? Also estimate how many that is in pint glasses and olympic-size swimming pools that would fill? Finally, estimate how many water droplets that is? Please show your work, because struggling to understand how to solve this problem, thank you.

Explanation / Answer

a)

depth of the water d=2 inches

d=2*(0.083 ft)

d=0.167 ft

and

area of the town A=14.3 mile^2

A=14.3*640 Acres

A=9152 Acres

now,

volume of water v=A*d

v=9152*0.167 acre.ft

v=1528.384 acre.ft

b)

v=1528.384 acre.ft

or

v=1528.4*(4046.86*0.305)

v=1.89*10^6 m^3

and

1m^3=2113.4 pint

therefore,

no of pints=(1.89*10^6/2113.4)=894.3

c)

1m^3=1.22*10^7 waterdrops

no of waterdroplets =1.89*10^6/(1.22*10^7)=0.155

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.