Asume that where m is the mass of the cart, and g =9.8 m / s 2 is the accelerati

Question

Asume that where m is the mass of the cart, and g=9.8 m/s2 is the acceleration of the free fall.

When you hold the cart with a kitchen scale parallel to the track so that the cart's acceleration is zero along horizontal track, what is the amount of force you are applying?

A. Depends on the angle at which you hold it  

B. 0 N

C. (m · g) N

Now you raise the track to an angle with the horizontal and the cart's acceleration is zero with the scale parallel to the track, what is the amount of force you are applying?

A. 0 N

B. (m · g · sin()) N   

C. 0 N when the cart is stationary and a larger force when the cart is moving with constant velocity

D. (m · g · cos())N

E. Larger force when the cart is stationary and a smaller force when the cart is moving with constant velocity

Finally you increased the angle between the direction of the pull and the surface of the track to be while the cart has zero acceleration and the track angle as before. What is the amount of force you are applying? (Can be multiple answers)

A. (m · g · sin() · cos()) N

B. 0 N

D. (m · g · cos(+) )N

E. (m · g · sin(+) )N

F. (m · g) N

G. Larger amount of force compared to when the pull was parallel to the track

H. Smaller amount of force compared to when the pull was parallel to the track

Explanation / Answer

1.
If mass is on the horizontal track .There is no force acting on it in horizontal direction.
So Horizontal force applied = 0
Answer: 0 N

2.
When the track angle is , net force acting along track is m*g*sin
You must balance this force
Answer: B

3.
Lets say you apply a force F at angle from surface of track
Your force along the track is F * cos
This force must balance m*g*sin
so,
F * cos =m*g*sin
F= (m*g*sin )/cos

since cos is less than 1, f will be larger than when was 0

Answer: C and G

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