A 224-kg log is pulled up a ramp by means of a rope that is parallel to the surf

Question

A 224-kg log is pulled up a ramp by means of a rope that is parallel to the surface of the ramp. The ramp is inclined at 30.0° with respect to the horizontal. The coefficient of kinetic friction between the log and the ramp is 0.824, and the log has an acceleration of 0.611 m/s2. Find the tension in the rope. A 224-kg log is pulled up a ramp by means of a rope that is parallel to the surface of the ramp. The ramp is inclined at 30.0° with respect to the horizontal. The coefficient of kinetic friction between the log and the ramp is 0.824, and the log has an acceleration of 0.611 m/s2. Find the tension in the rope. A 224-kg log is pulled up a ramp by means of a rope that is parallel to the surface of the ramp. The ramp is inclined at 30.0° with respect to the horizontal. The coefficient of kinetic friction between the log and the ramp is 0.824, and the log has an acceleration of 0.611 m/s2. Find the tension in the rope.

Explanation / Answer

Gravitational force F = mg = 224 *0.611 = 136.86 N

Force Normal F = mg cos theta 2197.44* 0.866 = 1903.03 N

Frictional force Ff = uMg = 0.611 * 2197.44 = 1342.63 N

Component of force parallel to incline is F = 224 * 9.8 sin 30 = 1098.72 N

so

Tension T = 1903.03 + 1098.72 - 136.84 = 2864.91 N

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